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Page Name: application of curve tracing ppt
Created at: Tuesday 11th of June 2013 08:59:54 AM
Last Edited Or Replied at :Tuesday 11th of June 2013 08:59:54 AM
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Page Name: CYCLIC REDUNDANCY CHECK pdf
Posted by: engineering project helper
Created at: Monday 03rd of December 2012 08:06:47 AM
Last Edited Or Replied at :Monday 25th of March 2013 06:37:40 AM
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|he remainder on dividing it by a fairly large prime such as|
Intuitively, one would expect this to give a reliable checksum.
To develop a hardware circuit for computing the CRC checksum, we reduce the
polynomial division process to its essentials.
The process employs a shift register, which we denote by CRC. This is of
length r (the degree of G) bits, not as you might expect. When the subtractions
(exclusive or’s) are done, it is not necessary to represent the high-order bit,
because the high-order bits of G and the quantity it is being subtracted from are
both 1...................==> [ Click Here to Read More ]
Created at: Friday 13th of July 2012 04:27:14 PM
Last Edited Or Replied at :Sunday 22nd of July 2012 02:34:47 PM
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|Please provide the powerpoint presentation on future of indian mathematics.|
It is very much necessary for me as i have been selected by my school to give a seminars on the future of indian mathematics .
So if it is possible,please then definitely provide me with the presentation.
A Student in desperation
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Page Name: maths basic
Posted by: project ideas
Created at: Wednesday 04th of July 2012 05:29:37 AM
Last Edited Or Replied at :Wednesday 04th of July 2012 05:29:37 AM
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| maths basic|
Basic properties of R, Absolute value, Intervals on the real line, Functions (Definition and examples), Inverse functions, Graphs of functions, Operations on functions, Composite of functions, Even and odd functions, Monotone functions, Periodic functions.
Definition of limits, Algebra of limits, Limits as (or ), One-sided limits, Continuity (Definitions and Examples, Algebra of continuous functions),
Definition of derivative of a function, Derivatives of some ..................==> [ Click Here to Read More ]
Posted by: project ideas
Created at: Tuesday 03rd of July 2012 06:50:01 AM
Last Edited Or Replied at :Tuesday 03rd of July 2012 06:50:01 AM
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|Implementation of back-propagation neural networks with
The artificial neural network back propagation algorithm is implemented in Matlab
language. This implementation is compared with several other software packages.
The effect of reducing the number of iterations in the performance of the algorithm
iai studied. The speed of the back propagation program, mkckpmp, written in Matlab
language is compared with the speed of several other back propagation programs
which are written in the C language. The speed of th..................==> [ Click Here to Read More ]
Posted by: academic expert
Created at: Monday 02nd of May 2011 09:43:45 AM
Last Edited Or Replied at :Monday 02nd of May 2011 09:43:45 AM
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|xt, we wanted to analyze the mathematical content and|
its ulterior motives using fuzzy analysis. We analyzed this
problem using fuzzy models like Fuzzy Cognitive Maps (FCM),
Fuzzy Relational Maps (FRM) and the newly constructed fuzzy
dynamical system (and its Neutrosophic analogue) that can
analyze multi-experts opinion at a time using a single model.
The issue of Vedic Mathematics involves religious politics,
caste supremacy, apart from elementary arithmetic—so we
cannot use simple statistics for our analysis. Further any study,
when scientifically carried out using fuzzy models ha..................==> [ Click Here to Read More ]
Page Name: HCF AND LCM OF NUMBERS
Posted by: academic expert
Created at: Monday 04th of April 2011 07:57:02 AM
Last Edited Or Replied at :Monday 04th of April 2011 07:57:02 AM
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| numerator is the greatest.|
Ex. 1. Find the H.C.F. of 23 X 32 X 5 X 74, 22 X 35 X 52 X 73,23 X 53 X 72
Sol. The prime numbers common to given numbers are 2,5 and 7.
H.C.F. = 22 x 5 x72 = 980.
Ex. 2. Find the H.C.F. of 108, 288 and 360.
Sol. 108 = 22 x 33, 288 = 25 x 32 and 360 = 23 x 5 x 32.
H.C.F. = 22 x 32 = 36.
Ex. 3. Find the H.C.F. of 513, 1134 and 1215.
1134 ) 1215 ( 1
81 ) 1134 ( 14
H.C.F. of 1134 and 1215 is 81.
So, Required H.C.F. = H.C..................==> [ Click Here to Read More ]
Posted by: seminar topic helper
Created at: Tuesday 05th of October 2010 07:58:48 AM
Last Edited Or Replied at :Tuesday 05th of October 2010 07:58:48 AM
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| many geometrical problems in image analysis which cannot be solved on the basis of classical
In this projects we introduced a new notion of Abstract Cell Complex (ACC) which is independent of Euclidean geometry and based on locally finite T0 topological space. Further, we introduced the boundary, frontier and connectivity among the abstract elements using the notion of closed set, open set and more importantly smallest neighborhood of elements in cell complexes. Finally we established the result every finite topological space with separation property is isomorphic to an ..................==> [ Click Here to Read More ]
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